Two objects attract each other with a gravitational force of magnitude 1.00 10-8 N when separated by 19.3 cm. If the total mass of the objects is 5.05 kg, what is the mass of each?
F=1.0×10−8 Nr=19.3×10−2 mm1+m2=5.05F = 1.0 \times 10^{-8} \;N \\ r = 19.3 \times 10^{-2} \;m \\ m_1+m_2=5.05F=1.0×10−8Nr=19.3×10−2mm1+m2=5.05
From Newton’s law of force
F=Gm1m2r21.0×10−8=6.67×10−11×m1m2(19.3×10−2)25.584=m1m2m1+m2=5.05m1=5.05−m25.584=(5.05−m2)m25.584=5.05m2−m22m22−5.05m2+5.584=0m2=3.41m1=1.64F = \frac{Gm_1m_2}{r^2} \\ 1.0 \times 10^{-8} = \frac{6.67 \times 10^{-11} \times m_1m_2}{(19.3 \times 10^{-2})^2} \\ 5.584 = m_1m_2 \\ m_1+m_2=5.05 \\ m_1 = 5.05 -m_2 \\ 5.584 = (5.05 -m_2)m_2 \\ 5.584 = 5.05m_2 -m_2^2 \\ m^2_2 -5.05m_2 + 5.584 = 0 \\ m_2 = 3.41 \\ m_1 = 1.64F=r2Gm1m21.0×10−8=(19.3×10−2)26.67×10−11×m1m25.584=m1m2m1+m2=5.05m1=5.05−m25.584=(5.05−m2)m25.584=5.05m2−m22m22−5.05m2+5.584=0m2=3.41m1=1.64
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments