Answer to Question #257625 in Molecular Physics | Thermodynamics for Jay

Question

The density of a gas is 0.28 1b/ft. What volume does 12.0 lbs of the gas occupy? What is the specific volume of the gas?

Answer 1

Density$\rho=0.28lb/ft^3=4.48517kg/m^3$

$Mass=12lbs=5.44311kg$

$Volume (v)=\frac{m}{\rho}$

Put value

$v=\frac{5.44311}{4.48517}=1.213m^3$

Specific volume

$V'=\frac{v}{m}$

Where (m)=5.44311kg

$V'=\frac{1.214}{5.44311}=0.22m^3/kg$