Steam expands steadily at a constant temperature. The flow rate is 13.6 kg/min with an inlet state of wet steam (water) at 80% quality to a final state of 700C and 2.5 MPa. The change of kinetic energy across the device is 3.5 kJ/kg, and the heat added is 21.81 kW. Determine (a) the enthalpy of conditions 1 &2, (b) the heat transfer in kJ/kg, (c) the work, and (d) the system power.
(a) Mass flow rate = 13.6 kg/min
Inlet state quality (x) = 0.8
Final state : temperature T2 = 70 °C
P2 = 2.5 MPa.
Change in kinetic energy = 3.5 KJ/Kg
Heat added (Q) = 21.81 KW
Steam is expanding at constant temperature
Therefore T1 = T2
or T1 = 70 °C
And x = 0.8
at temperature T = 70 °C
hf = 293.02 KJ/Kg
hg = 2626.01 KJ/Kg
So h1 = hf + x × (hg- hf)
= 293.02 + 0.8×(2626.01-293.02)
= 2159.41 KJ/Kg
P2 = 2.5 MPa
T2= 70 °C
At this set of temperature and pressure fluid is in liquid state.
h2 = 295.04 KJ/Kg
(b) Heat transfer in KJ/ Kg
Heat transfer = 21.81 KW
Mass flow rate = 13.6 Kg/ min
So heat transfer in KJ/Kg
=96.08 KJ/Kg
(c) Energy equation per unit mass
(d) System power
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