Answer to Question #254684 in Molecular Physics | Thermodynamics for PUMAH LUTRA

Question

1.) Two spheres of mass 1.0kg and 4.0kg are joined by a light rod so that their centers are 0.20m apart. Calculate the position of center of gravity.

Answer 1

Given:

$m_1=1.0\:\rm kg$

$m_2=4.0\:\rm kg$

$l=0.20\:\rm m$

The center of gravity of the system

$$x_c=\frac{x_1m_1+x_2m_2}{m_1+m_2}=\frac{0*m_1+l*m_2}{m_1+m_2}$$

$$x_c=\frac{0.20*4.0}{1.0+4.0}=0.16\:\rm m\quad(from\;\it m_{\rm1})$$