Question #25279

The temperature of a body is increased from -173 C to 357 C. What is the ratio of energies emitted by the body per second in these two cases?

Expert's answer

QUESTION:

The temperature of a body is increased from -173 C to 357 C. What is the ratio of energies emitted by the body per second in these two cases?

ANSWER

According to the Stefan-Boltzmann law the total energy radiated per unit surface area of a black body across all wavelengths per unit time is ε=σT4\varepsilon = \sigma T^4

Hence (-173 C = 100 K, 357 C = 630 K)


ε1ε2=(T1T2)4\frac{\varepsilon_1}{\varepsilon_2} = \left(\frac{T_1}{T_2}\right)^4ε1ε2=(100630)4=6.348104\frac{\varepsilon_1}{\varepsilon_2} = \left(\frac{100}{630}\right)^4 = 6.348 \cdot 10^{-4}

ANSWER

ε1ε2=6.348104\frac{\varepsilon_1}{\varepsilon_2} = 6.348 \cdot 10^{-4}

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