Constant Pressure Process
P = 3.5 bar
Heat added = 25 kJ = 25000 J
For Constant Pressure Process, Work Done is given as
Negative sign indicates that the work is done on the system
Internal Energy
From First Law we have
ΔU = Q – W
ΔU = 25000 – (– 31500)
ΔU = 25000 + 31500
ΔU = 56500 J
Change in Internal Energy = 56500 J
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