Question #251926

Superheated steam at 2 bar and 150oC is compressed isothermally. The steam in its final state is wet steam with a specific volume of 0.3511 m3 /kg.

Determine the change of enthalpy per kg of steam.


1
Expert's answer
2021-10-18T11:02:36-0400

mMRT1=p1V1=p2V2,\frac mMRT_1=p_1V_1=p_2V_2,

p2=RT1MmV2=3.45 bar,p_2=\frac{RT_1} M\cdot \frac m{V_2}=3.45~bar,

m=p2V2MRT1=0.45 kg,m=\frac{p_2V_2M}{RT_1}=0.45~kg,

H=γnRγ1=2.18 JK.H=\frac{\gamma nR}{\gamma -1}=2.18~\frac JK .


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