If a ½ hp pump runs for 21 minutes, what is the energy used in kW-hr?
1 HP = 0.75 kW
0.752=0.375 kW per 21 min\frac{0.75}{2} = 0.375 \;kW \; per \; 21\; min20.75=0.375kWper21min
Proportion:
0.375 kW – 21 min
x kW – 60 min
x=0.375×6021=1.071 kW−hrx = \frac{0.375 \times 60}{21} = 1.071 \;kW-hrx=210.375×60=1.071kW−hr
Answer: 1.071 kW-hr
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