Question #248895

John kicks the ball, and the ball does a projectile motion with an angle of 53o to horizontal with an initial velocity of 10 m/s. What is (a) its maximum height, (b) its maximum distance, and (c) its hangtime?


1
Expert's answer
2021-10-10T15:56:21-0400

(a)

Hmax=u2sin2θ2g=102×sin2532×9.81=3.25086  mH_{max} = \frac{u^2sin^2 θ}{2g} \\ = \frac{10^2 \times sin^2 53}{2 \times 9.81} \\ = 3.25086 \;m

(b)

Rmax=u2sin2θg=102sin(2×53)9.81=9.7988  mR_{max} = \frac{u^2 sin2θ }{g} \\ = \frac{10^2 sin(2 \times 53)}{9.81} \\ = 9.7988 \;m

(c)

T=2usinθg=2×10×sin539.81=1.6282  sT= \frac{2u sin θ}{g} \\ = \frac{2 \times 10 \times sin53}{9.81} \\ = 1.6282 \;s


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