John kicks the ball, and the ball does a projectile motion with an angle of 53o to horizontal with an initial velocity of 10 m/s. What is (a) its maximum height, (b) its maximum distance, and (c) its hangtime?
(a)
Hmax=u2sin2θ2g=102×sin2532×9.81=3.25086 mH_{max} = \frac{u^2sin^2 θ}{2g} \\ = \frac{10^2 \times sin^2 53}{2 \times 9.81} \\ = 3.25086 \;mHmax=2gu2sin2θ=2×9.81102×sin253=3.25086m
(b)
Rmax=u2sin2θg=102sin(2×53)9.81=9.7988 mR_{max} = \frac{u^2 sin2θ }{g} \\ = \frac{10^2 sin(2 \times 53)}{9.81} \\ = 9.7988 \;mRmax=gu2sin2θ=9.81102sin(2×53)=9.7988m
(c)
T=2usinθg=2×10×sin539.81=1.6282 sT= \frac{2u sin θ}{g} \\ = \frac{2 \times 10 \times sin53}{9.81} \\ = 1.6282 \;sT=g2usinθ=9.812×10×sin53=1.6282s
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