Question #248292

Determine the net heat radiated by the black body disc of mass 6g and radius 4cm at 400C, initially kept at 300C.


1
Expert's answer
2021-10-11T16:16:46-0400

Solution;

By Stefan-Boltzmann's law of radiation,the net rate of heat transfer by radiation is;

Qnett=σAe(T24T14)\frac {Q_{net}}{t}=\sigma Ae(T_2^4-T_1^4)

For a black body,e=1

A=πr2=π×0.042=A=πr^2=π×0.04^2=5.026×10-3m2

Qnett=5.67×108×5.026×103×(31343034)\frac{Q_{net}}{t}=5.67×10^{-8}×5.026×10^{-3}×(313^4-303^4)

Qnett=0.33331J/s\frac{Q_{net}}{t}=0.33331J/s








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