Question #246998

An automobile tire is inflated to 35 psig at 54 oF. After being driven, the temperature rise to 80 oF. Determine the final gage pressure assuming volume remains constant


1
Expert's answer
2021-10-05T15:43:57-0400

Assuming ideal gas low

Process is Isochoric

pV=nRTpV=RTpT=RV=constantp1T1=p2V2p2=p1×T2T1T1=54=285  KT2=80=299  Kp2=35×299285=36.72  psigpV=nRT \\ pV = RT \\ \frac{p}{T} = \frac{R}{V} = constant \\ \frac{p_1}{T_1} = \frac{p_2}{V_2} \\ p_2 = \frac{p_1 \times T_2}{T_1} \\ T_1 = 54 =285 \;K \\ T_2 = 80 =299 \;K \\ p_2= \frac{35 \times 299}{285} = 36.72 \;psig


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