Question

A rubber chicken is launched straight up at speed v from ground level. Find each of the following if the launch speed is tripled (in terms of any constants and v).

Answer 1

Given,

Initial launcher speed = v

If initial launcher speed =3v

a) Let, initially the maximum height was h, and finally it was H

Applying newton's law of motion,

$v^2= u^2-2gh$

Now, at the maximum height v=0

$\Rightarrow 0=v^2-2gh$

$h=\frac{v^2}{2gh}$

and finally $H=\frac{9v^2}{2g}$

b)

Let the time of hang is T, and time taken to reach at maximum height = t

Now, $v=u-gt$

at the top most point, final velocity of the object = 0

$\Rightarrow 0=v-gt$

$\Rightarrow t= \frac{v}{g}$

Hence, initially the time of flight of the projectile $(T)=2t = \frac{2v}{g}$

and for the final condition,

$T' = \frac{6v}{g}$

c)

The impact speed will be v if it was projected with v and it will be 3v, if it is projected with 3v.

but if $3v\ge V_{esc}$ ,

then it will not come back in the gravitational field.