An iron railway line is 30m long at a temperature of 27oC. What would be the length of the
railway line when the temperature increases to 57oC? The coefficient of linear expansion of
iron is 1.2 x 10-5 oC-1
Solution.
L=30m;L=30m;L=30m;
t1=27oC;t_1=27^oC;t1=27oC;
t2=57oC;t_2=57^oC;t2=57oC;
α=1.2⋅10−5C−1;\alpha=1.2\sdot10^{-5}C^{-1};α=1.2⋅10−5C−1;
L0=L1+αΔT;L_0=\dfrac{L}{1+\alpha \Delta T};L0=1+αΔTL;
L0=301+1.2⋅10−5⋅7=29.99m;L_0=\dfrac{30}{1+1.2\sdot10^{-5}\sdot7}=29.99m;L0=1+1.2⋅10−5⋅730=29.99m;
L1=L0(1+αΔT);L1=L_0(1+\alpha \Delta T);L1=L0(1+αΔT);
L1=29.99(1+1.2⋅10−5⋅37)=30.003m;L_1=29.99(1+1.2\sdot10^{-5}\sdot37)=30.003m;L1=29.99(1+1.2⋅10−5⋅37)=30.003m;
Answer: L1=30.003m.L_1=30.003m.L1=30.003m.
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