A pendulum makes 90 vibrations in a minute.
a.) Find the period T in seconds.
b.) What is its frequency?
a.T=(a/60s)/90==a60×90=a5400 sa.\\ T= (a/60_s)/90=\\ =\frac{a}{{60}\times{90}}\\ =\frac{a}{5400}\; sa.T=(a/60s)/90==60×90a=5400as
b.
F=1T=5400a HzF=\frac{1}{T}\\ =\frac{5400}{a}\;\;HzF=T1=a5400Hz
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