Question

a sample nitrogen gas undergoes an adiabatic expansion. The initial pressure and volume of the gas is 4.00 atm and 14.0 L. The final volume is 30.0L. If there are 2 moles of gas, determine the following

Answer 1

Solution.

$P_i=4.00 atm;$

$V_i=14.0L;$

$V_f=30.0L;$

$\gamma=1.4;$

$\dfrac{P_f}{P_i}=(\dfrac{V_i}{V_f})^\gamma\implies P_f=P_i(\dfrac{V_i}{V_f})^\gamma;$

$P_f=4.00\sdot(\dfrac{14.0}{30.0})^{1.4}=1.38 atm;$

Answer: $P_f=1.38 atm.$