At a party 0.50 kg tube ice at -10 degrees C is placed in 3.0 kg of iced tea at 20 degrees C . At what temperature will be the final mixture be?The tea can be considered as water.Assume a heat flow sorroundings and the container.
Heat gain = Heat loss
1
Expert's answer
2013-02-13T09:02:45-0500
The heat offusion of water ice is 334 kJ/kg. Ice heat capacity is 2.11 kJ / (kg * K) Water heat capacity (for temperature above zero) is 4.1813 kJ / (kg * K).
Let's assume the final mixture is totally liquid at temperature T above zero in Celsius scale. Then the heat balance equation is
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment