Question #240856

Under normal conditions the human heart converts about 13.3 J of chemical energy per second into 1.33 W of mechanical power as it pumps blood throughout the body.


(a)

Determine the number of Calories required to power the heart for one day, given that 1 Calorie equals 4186 J.

__ Cal


(b)

Metabolizing 1 kg of fat can release about 9000 Calories of energy. What mass of metabolized fat (in kg) would power the heart for one day?

__ kg


1
Expert's answer
2021-09-23T15:48:38-0400

In one day =13.3×86400  s=1149120  J= 13.3 \times 86400 \;s = 1149120\; J

=11491284186=274.52  cal= \frac{1149128}{4186} \\ = 274.52 \;cal

(b) 1 kg = 9000 cal

274.52  cal=274.529000  kg=0.0305  kg274.52 \;cal = \frac{274.52}{9000} \;kg \\ = 0.0305 \;kg


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Comments

Jb
03.08.22, 21:32

Awesome

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