Find a) the mass in kilograms and b) rms speed for sulfur dioxide S02 at room temperature 20°C. mass5 = 32.065u
Mass=32.065amu
1amu=1.67×10−27kg1amu=1.67\times10^{-27}kg1amu=1.67×10−27kg
VRMS=3KTMV_{RMS}=\sqrt{\frac{3KT}{M}}VRMS=M3KT
Mso2=64.1×10−3kg/molM_{so_2}=64.1\times10^{-3}kg/molMso2=64.1×10−3kg/mol
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