Question #240571

Find a) the mass in kilograms and b) rms speed for sulfur dioxide S02 at room temperature 20°C. mass5 = 32.065u


1
Expert's answer
2021-09-22T08:15:03-0400

Mass=32.065amu

1amu=1.67×1027kg1amu=1.67\times10^{-27}kg


M=32.065×1.67×1027=5.35×1026kgM=32.065\times1.67\times10^{-27}=5.35\times10^{-26}kg

VRMS=3KTMV_{RMS}=\sqrt{\frac{3KT}{M}}

Mso2=64.1×103kg/molM_{so_2}=64.1\times10^{-3}kg/mol


VRMS=3×8.314×29364.1×103=337.65m/secV_{RMS}=\sqrt{\frac{3\times8.314\times293}{64.1\times10^{-3}}}=337.65m/sec


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