Question #235913

Figure A shows the variation of pressure (in atm) with volume (in L) for one [3] mole of an ideal gas. Calculate the heat (QAR) and work done from state A to state B in joules (WA) if change in internal energy (AUsa) is 50 cal.

Expert's answer

We know that

Thermodynamics first law

dQ=dU+PdVdQ=dU+PdV

dQ=50×4.2+1×RTdQ=50\times4.2+1\times RT

dQ=50×4.2+1×8.31TdQ=50\times4.2+1\times 8.31T

dQ=210+RTdQ=210+ RT

Work


W=PdVW=PdV

PdV=nRT

W=PdV=RT=8.31TJW=PdV=RT=8.31T J


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