Answer to Question #235284 in Molecular Physics | Thermodynamics for Jimmy

Question #235284

Find the enthalpy of Helium if its internal energy is 200 KJ/kg


h = _____ kJ/kg


1
Expert's answer
2021-09-12T19:21:42-0400

Gives

U=200KJ/kg

U=mcvTH=mcpTU=mc_vT\\H=mc_pT

Now

HU=mcpTmcvTHU=cpcv\frac{H}{U}=\frac{mc_pT}{mc_vT}\\\frac{H}{U}=\frac{c_p}{c_v}

Helium is monoatomic

cpcv=53\frac{c_p}{c_v}=\frac{5}{3}


H=cvcp×U=53×200=333.33kJ/kgH=\frac{c_v}{c_p}\times U=\frac{5}{3}\times200=333.33kJ/kg

h=H=333.33kJ/kgh=H=333.33kJ/kg


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