Question #233157

A gas is compressed from 120 kPa and 15oC to 800 kPa. Calculate the final temperature when

the process is

i. Isothermal (n=1)

ii. Polytropic (n=1.3)

iii Adiabatic (γ=1.4)

iv. Polytropic (n= 1.5)


1
Expert's answer
2021-09-04T18:21:12-0400

Solution.

i. T2=T1=15oC;T_2=T_1=15^oC;

ii. T2=T1(p2/p1)11/n=288(800/120)0.231=446K=173oC;T2 = T1 (p2 / p1)^{ 1-1/n} = 288(800/120)^{0.231} = 446 K= 173^oC;

III.T2=T1(p2/p1)11/γ=288(800/120)0.286=495K=222oC;T_2 = T_1 (p_2 / p_1)^{ 1-1/γ} = 288(800/120)^{0.286} = 495 K= 222^oC;

iv.T2=T1(p2/p1)11/n=288(800/120)0.333=541K=269oC;T_2 = T_1 (p_2 / p_1)^{ 1-1/n }= 288(800/120)^{0.333} = 541 K =269^oC;

Answer: i.T2=15oC;i. T_2=15^oC;

ii.T2=173oC;ii. T_2=173^oC;

iii.T2=222oC;iii. T_2=222^oC;

iv.T2=269oC;iv. T_2=269^oC;



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