A gas is compressed from 120 kPa and 15oC to 800 kPa. Calculate the final temperature when
the process is
i. Isothermal (n=1)
ii. Polytropic (n=1.3)
iii Adiabatic (γ=1.4)
iv. Polytropic (n= 1.5)
Solution.
i. "T_2=T_1=15^oC;"
ii. "T2 = T1 (p2 \/ p1)^{\n1-1\/n} = 288(800\/120)^{0.231} = 446 K= 173^oC;"
III."T_2 = T_1 (p_2 \/ p_1)^{\n1-1\/\u03b3}\n = 288(800\/120)^{0.286} = 495 K= 222^oC;"
iv."T_2 = T_1 (p_2 \/ p_1)^{\n1-1\/n }= 288(800\/120)^{0.333} = 541 K =269^oC;"
Answer: "i. T_2=15^oC;"
"ii. T_2=173^oC;"
"iii. T_2=222^oC;"
"iv. T_2=269^oC;"
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