Solution.
i.  T2=T1=15oC;  
ii. T2=T1(p2/p1)1−1/n=288(800/120)0.231=446K=173oC;  
III.T2=T1(p2/p1)1−1/γ=288(800/120)0.286=495K=222oC; 
iv.T2=T1(p2/p1)1−1/n=288(800/120)0.333=541K=269oC; 
Answer: i.T2=15oC; 
                ii.T2=173oC; 
                iii.T2=222oC; 
                 iv.T2=269oC; 
                             
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