Question

Calculate the maximum monochromatic emissive power at 288K?

Answer 1

According to Wien's displacement  law, we have

$$\lambda=\frac bT.$$

The maximum monochromatic emissive power is

$$E=\frac{2hc^2}{\lambda^5}·\frac{1}{e^{\frac{hc}{\lambda kT}}-1}.$$

Substitute the wavelength:

$$E=\frac{2hc^2T^5}{b^5}·\frac{1}{e^{\frac{hc}{b k }}-1}=8.12·10^6\text{ W/m}^2.$$