Answer to Question #232133 in Molecular Physics | Thermodynamics for Arisco

Question #232133
Calculate the maximum monochromatic emissive power at 288K?
1
Expert's answer
2021-09-02T10:41:37-0400

According to Wien's displacement  law, we have

λ=bT.\lambda=\frac bT.


The maximum monochromatic emissive power is


E=2hc2λ51ehcλkT1.E=\frac{2hc^2}{\lambda^5}·\frac{1}{e^{\frac{hc}{\lambda kT}}-1}.

Substitute the wavelength:


E=2hc2T5b51ehcbk1=8.12106 W/m2.E=\frac{2hc^2T^5}{b^5}·\frac{1}{e^{\frac{hc}{b k }}-1}=8.12·10^6\text{ W/m}^2.


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