Question #229472

Two spheres of same material and radii 5m and 2m are at temperature 200K and 2500K respectively.The ratio of energies radiated by them per second is

Expert's answer

Gives

r1=5mr2=2mT1=200KT2=2500Kr_1=5m\\r_2=2m\\T_1=200K\\T_2=2500K

We know that stefan's law

E=σAT4E=\sigma AT^4

E1E2=A1T14A2T24\frac{E_1}{E_2}=\frac{A_1T_1^4}{A_2T_2^4}

E1E2=r12T14r2T24\frac{E_1}{E_2}=\frac{r_1^2T_1^4}{r_2T_2^4}

r1r2=52\frac{r_1}{r_2}=\frac{5}{2}

E1E2=254×(2002500)4=415625\frac{E_1}{E_2}=\frac{25}{4}\times(\frac{200}{2500})^4=\frac{4}{15625}


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