Energy flow Q = 142 L/min
Boundary to system P= 108.5 kJ/min
P=60sec108.5×103JP=1808.3WP=1.81kW
We know that,
P=Time(t)Workdone(W)=TimeForce×distanceP=Force(F)×VVelocityV=TimedistanceP=P1×A×VPressure(P1)=AFP=P1×QEnergyflowQ=A×V
Putting values
P1=QP=0.142m3/min1.81kW×60sec=764.78kPa
Answer: 764.78 kPa
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