Answer to Question #228856 in Molecular Physics | Thermodynamics for Thorfinn

Question #228856

The flow energy of 142 liters/min of a fluid passing a boundary to a system is 108.5 kJ/min. Determine the pressure at this point. 

p = ___ kPa

Answer in 2 decimal places


1
Expert's answer
2021-08-25T13:55:47-0400

Energy flow Q = 142 L/min

Boundary to system P= 108.5 kJ/min

P=108.5×103  J60  secP=1808.3  WP=1.81kWP= \frac{108.5 \times 10^3\;J}{60\;sec} \\ P= 1808.3 \;W \\ P=1.81 kW

We know that,

P=Work  done  (W)Time  (t)=Force×distanceTimeP=Force  (F)×VVelocity  V=distanceTimeP=P1×A×VPressure  (P1)=FAP=P1×QEnergy  flow  Q=A×VP= \frac{Work \; done \;(W)}{Time \; (t)} = \frac{Force \times distance}{Time} \\ P= Force \; (F) \times V \\ Velocity \; V = \frac{distance}{Time} \\ P=P_1 \times A \times V \\ Pressure \;(P_1) = \frac{F}{A} \\ P = P_1 \times Q \\ Energy \; flow \; Q = A \times V

Putting values

P1=PQ=1.81  kW×60  sec0.142  m3/min=764.78  kPaP_1 = \frac{P}{Q} = \frac{1.81 \;kW \times 60 \;sec}{0.142\;m^3/min} \\ = 764.78 \;kPa

Answer: 764.78 kPa


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