The flow energy of 142 liters/min of a fluid passing a boundary to a system is 108.5 kJ/min. Determine the pressure at this point.
p = ___ kPa
Answer in 2 decimal places
Energy flow Q = 142 L/min
Boundary to system P= 108.5 kJ/min
"P= \\frac{108.5 \\times 10^3\\;J}{60\\;sec} \\\\\n\nP= 1808.3 \\;W \\\\\n\nP=1.81 kW"
We know that,
"P= \\frac{Work \\; done \\;(W)}{Time \\; (t)} = \\frac{Force \\times distance}{Time} \\\\\n\nP= Force \\; (F) \\times V \\\\\n\nVelocity \\; V = \\frac{distance}{Time} \\\\\n\nP=P_1 \\times A \\times V \\\\\n\nPressure \\;(P_1) = \\frac{F}{A} \\\\\n\nP = P_1 \\times Q \\\\\n\nEnergy \\; flow \\; Q = A \\times V"
Putting values
"P_1 = \\frac{P}{Q} = \\frac{1.81 \\;kW \\times 60 \\;sec}{0.142\\;m^3\/min} \\\\\n\n= 764.78 \\;kPa"
Answer: 764.78 kPa
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