Question #227952
A gasoline engine with a thermal efficiency of 28% has a power out put of 50hp . How much heat must be supplied per second to the engine
1
Expert's answer
2021-08-23T12:41:48-0400

By definition, the efficiency is given as follows:


η=PoutPin×100%\eta = \dfrac{P_{out}}{P_{in}}\times 100\%

where Pout=50hpP_{out} = 50hp is the output power of the engine, and PinP_{in } is the heat supplied per second to the engine. Thus, obtain:


Pin=Poutη×100%=50hp28%×100%179hpP_{in} = \dfrac{P_{out}}{\eta}\times 100\% = \dfrac{50hp}{28\%}\times 100\% \approx 179hp

Answer. 179 hp.


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