Question

4. determine the initial temperature of 225 g of water that absorbs 300. J of heat and ends at a temperature of 87.5 oC.

Answer 1

Question 22239

The amount of energy, that water absorbs is connected with changes in temperature by this formula: $Q = c m \Delta T = c m (T_{1} - T_{0})$ , where $c$ is heat capacitance, $m$ is the mass, and $\Delta T$ is the difference in temperature at the beginning and end. For water, $c = 4200$ .

Hence, $300J = 4200\frac{J}{kg}\frac{225}{1000} kg(87,5 - T_0)\Rightarrow T_0 = 87,1825{}^\circ$