Question

The temperature in a refrigerator coil is 267K and that in the condenser coil is 295K. Assuming that the machine operates on the reversed Carnot cycle, calculate :

(i) C.O.P.(ref.)

(ii) The refrigerating effect per kW of input work.

(iii) The heat rejected to the condenser.

Answer 1

$$Cop=\frac{T_2}{T_1-T_2}=\frac{295}{295-267}=\frac{295}{28}=10.53$$

(2) COP =$\frac{refrigerating effect}{work input}$

Work input =$\\\frac{3.6\times10^6}{10.53}=341.88KJ$ (3)

Heat rejected to the condensor =COP$\times$ work done

$10.28\times341.88=3514.52$ kJ