Answer to Question #217890 in Molecular Physics | Thermodynamics for shutoy

Question

The cycle work of an air standard engine is 1000kJ/kg.The maximum cycle temperature is 3200 degree C and the temperature at the end of isentropic compression is 650 degrees Celsius. Calculate the compression ration of the engine

Answer 1

We know that

$PV^{\gamma-1}=constant$

$(\frac{V_2}{V_1})=\frac{T_2}{T_2}^{\gamma-1}$

Compressions ratio (r)=$\frac{V_2}{V_1}$

$$r=(\frac{T_2}{T_1})^{\gamma-1}=(\frac{3473}{923})^{1.5}=3.76^{1.5}=7.2$$