Question

What is the maximum guage pressure of water that can be measure by means of manometer tube, 2m high, density of water is 1000kg

Answer 1

Gives

Hight(h)=2m

$\rho=1000kg/m^3$

We know that

Gauge pressure

$$P=\rho gh=1000\times9.8\times2=19600pa$$

Put value

$P_G=P-P_0\\P_G=\rho gh-P_0$

$P_0=1atm=10^5pa$

$P=19600-10^5=80.400pa\\P_G=80.400pa$