Question #216362
A solid gold vase of mass 20.0 kg is suspended by a rope at sea bottom. What is the Buoyant Force of the seawater on the vase?
1
Expert's answer
2021-07-12T16:27:08-0400

Mass(m)=20.0kg

Gravity (g)=9.8m/sec2

Buoyant force (Fb)=mg

Fb=20×9.8=196NF_b=20\times9.8=196N

Buoyant Force of the seawater on the vase

Fb=196NF_b=196N



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