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Answer to Question #216362 in Molecular Physics | Thermodynamics for Zexy
Question #216362
A solid gold vase of mass 20.0 kg is suspended by a rope at sea bottom. What is the Buoyant Force of the seawater on the vase?
Expert's answer
Mass(m)=20.0kg
Gravity (g)=9.8m/sec2
Buoyant force (Fb)=mg
"F_b=20\\times9.8=196N"
Buoyant Force of the seawater on the vase
"F_b=196N"
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