Question

A solid gold vase of mass 20.0 kg is suspended by a rope at sea bottom. What is the Buoyant Force of the seawater on the vase?

Answer 1

Mass(m)=20.0kg

Gravity (g)=9.8m/sec²

Buoyant force (F_b)=mg

$F_b=20\times9.8=196N$

Buoyant Force of the seawater on the vase

$F_b=196N$