Question

What is the total charge output of the circuit below? 6F 3F CHE 12 F 6F 12 volt

Answer 1

Gives

$$C_1=6F,C_2=3F,C_3=12F,C_4=6F,V=12v$$

all capacitor are connected series combination

$\frac{1}{C_{net}}=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}+\frac{1}{C_4}$

$\frac{1}{C_{net}}=\frac{1}{6}+\frac{1}{3}+\frac{1}{12}+\frac{1}{6}$

$\frac{1}{C_{net}}=\frac{2+4+1+2}{12}$

$C_{net}=\frac{4}{3}$

Charge

$Q=CV$

Put value

$Q=\frac{4}{3}\times12=16C$