Question

A single stage reciprocating compressor takes 1 m3 of air per minute at 1.013 bar and 15°C and delivers it at 7 bar. Assuming that the law of compression ispv^1.35=c , and that clearance volume is negligible, calculate the indicated power.

Answer 1

$p_1=1.013 \;bar \\ T_1=288 \;K \\ V_1= 1 \;m^3/min \\ p_2= 7 \;bar \\ p_v^{1.35}=c \\ m_a= \frac{p_1V_1}{RT_1} \\ = \frac{1.013 \times 10^2 \times 1/60}{0.287 \times 288} = 0.02042 \;kg/s$

Delivery temperature

$\frac{T_2}{T_1}=(\frac{p_2}{p_1})^{\frac{n-1}{n}} \\ T_2=288(\frac{7}{1.013})^{\frac{0.35}{1.35}} = 475.2\;K$

The indicated power $= \frac{n}{n-1}mR(T_2-T_1)$

$= \frac{1.35}{0.35} \times 0.02042 \times 0.287 \times (475.2-288) =4.23 \;kW$