a venturimeter is used to measure liquid flow rate of 7.5x103L/min. the difference in pressure across the venturimeter is 8m of the flowing fluid. the pipe diameter is 0.19m. determine the throat diameter of the venturimeter. given Cd value is 0.96
Q=CdA1A2A12−A222gh(ρHgρ−1),Q=C_d\frac{A_1A_2}{\sqrt{A_1^2-A_2^2}}\sqrt{2gh(\frac{\rho_{Hg}}{\rho}-1)},Q=CdA12−A22A1A22gh(ρρHg−1),
A=πd24,A=\frac{\pi d^2}{4},A=4πd2,
d2=4π2ghCd2(ρHgρ−1)Q2+16π2d144=6.9 cm.d_2=\frac4{\pi \sqrt[4]{\frac{2ghC_d^2(\frac{\rho_{Hg}}{\rho}-1)}{Q^2}+\frac{16}{\pi^2 d_1^4}}}=6.9~cm.d2=π4Q22ghCd2(ρρHg−1)+π2d14164=6.9 cm.
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