Question

Q.1 the latent heat of fusion of water is 334j/g.how many grams of ice o^c will melt by the addition of 3034k/j of heat energy Q.2 A wave train has a period of 2.00 seconds and a wave length of 7.00 metres,how far will it travel in 8.00 seconds

Answer 1

Q.1 The latent heat of fusion of water is $334\mathrm{J}/\mathrm{g}$. How many grams of ice $0{}^{\circ}C$ will melt by the addition of $3034\mathrm{kJ}$ of heat energy.

Q.2 A wave train has a period of 2.00 seconds and a wave length of 7.00 meters. How far will it travel in 8.00 seconds.

Solution.

Q.1 $L = 334\frac{J}{g}, Q = 3034kJ = 3034000J$;

$$m - ?$$

The latent heat for a given mass of a ice is calculated by:

$$Q = Lm.$$

The mass of the ice is:

$$m = \frac{Q}{L}.$$ $$m = \frac{3034000J}{334\frac{J}{g}} = 9084g.$$

Q.2 $T = 2.00s, \lambda = 7.00m, t = 8.00s$;

$$l - ?$$

A wave train will travel:

$$l = vt.$$

A wave length is:

$$\lambda = vT;$$ $$v = \frac{\lambda}{T};$$ $$l = \frac{\lambda}{T} t.$$ $$l = \frac{7.00m}{2.00s} \cdot 8.00s = 28.00m.$$

Answer: Q.1 $m = 9084g$.

Q.2 $l = 28.00m$.