A gas has a temperature of 14 °C, and a volume of 4.5 L. If the temperature is raised to 29 °C and the pressure is not changed, what is the new volume of the gas? Round to the nearest tenth. Don't forget the units.
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Expert's answer
2012-12-24T11:05:17-0500
we have isobaric process here. Hence V1/T1 = V2/T2
where T1=14 C = (273+14) K = 287 K; T2=29 C = (273+29) K = 302 K V1=4.5L
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