Answer to Question #210084 in Molecular Physics | Thermodynamics for ray

Question

A sample containing 1.00 kmol of helium (treated as an ideal gas) is put 

through the cycle of operations shown in the figure. BC is an isotherm, 

and pA = 1.00 atm, VA = 22.4 m3

, pB = 2.00 atm.

'n 1.00 kmol monster helium (soos 'n ideale gas hanteer) ondergaan 'n stel 

prosesse in ‘n siklus, soos aangetoon in die figuur. BC is 'n isoterm, en pA

= 1.00 atm, VA = 22.4 m3

, pB = 2.00 atm.

a) Calculate the temperatures TA, TB and volume VC.

b) Calculate the work done during the cycle. Recall the expression for work done during an isothermal 

process.

Answer 1

a)

$T_A=\frac{p_AV_A}{\nu R}=273~K,$

$T_B=\frac{p_BV_B}{\nu R}=546~K,$

$V_C=\frac{p_B}{p_C} V_B=44.8~m^3,$

b)

$A=\nu RT_B\ln \frac{V_C}{V_B}=3.1~MJ.$