The distance between two crests of a long radio wave is 2.50 km. What is the frequency of this wave?
Solution.
λ=2.50km=2500m;\lambda=2.50km=2500m;λ=2.50km=2500m;
c=3⋅108m/s;c=3\sdot10^8m/s;c=3⋅108m/s;
λ=c/ν ⟹ ν=c/λ;\lambda=c/\nu\implies \nu=c/\lambda;λ=c/ν⟹ν=c/λ;
ν=3⋅108m/s2500m=1.2⋅105Hz;\nu=\dfrac{3\sdot10^8m/s}{2500m}=1.2\sdot10^5Hz;ν=2500m3⋅108m/s=1.2⋅105Hz;
Answer:ν=1.2⋅105Hz.\nu=1.2\sdot 10^5Hz.ν=1.2⋅105Hz.
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