Question

The horizontal distance between a point of equilibrium on a wave and the  middle of a crest is 2.50 m. What is the period if the wave travels 20.0 m  in 35.0 s?

Answer 1

Gives

A=2.50m

x=2.50m

t=35.0sec

$v=Aw$

$v=2.50\times\frac{2\pi}{T}\rightarrow equation(1)$

$v=\frac{x}{T}=\frac{20}{35}\rightarrow(2)$

Equation (1) and(2) are equal

$\frac{20}{35}=2.50\times\frac{2 \pi}{T}$

T=28 sec