What is the thermal energy removed to convert 0.5 kg of water at 0 degrees celsius to ice at 0 degrees celsius
The heat of fusion of water is 333.55 J/g
Therefore,
Q=cfm=333.55J/g×500g=166775J≈166.8kJQ=c_fm=333.55J/g\times500g=166775J\approx166.8kJQ=cfm=333.55J/g×500g=166775J≈166.8kJ
Answer: 166.8 kJ
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