Two forces of F =⟨75/√2 ,−75/√2⟩ N and F =⟨150/√2 ,−150/√2⟩ N act on an object. Find the third force F3 that is needed to balance the first two forces.
F′=F1+F2=⟨2252, −2252⟩,F'=F_1+F_2=⟨\frac{225}{\sqrt 2},~-\frac{225}{\sqrt 2}⟩,F′=F1+F2=⟨2225, −2225⟩,
F3=−F′=⟨−2252, 2252⟩.F_3=-F'=⟨-\frac{225}{\sqrt 2},~\frac{225}{\sqrt 2}⟩.F3=−F′=⟨−2225, 2225⟩.
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