When iron rusts in air, the following reaction occurs. What is the heat of formation of Iron(III) oxide?
4Fe(s)+3O2(g)=2Fe2O3(s) Delta H= -1643 KJ
The reaction of formation of 1 mole of Fe2O3 is following:
2Fe(s) + 1.5O2(g) --> Fe2O3(s)
If "\\Delta{H}" of formation of 2 moles of Fe2O3 is -1643 kJ, for 1 mole it will be equal to"\\frac{-1643kJ}{2}=-821.5kJ"
Answer: -821.5 kJ/mol
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