Question

1. A warehouse worker moves a crate weighing 100 N vertically a distance of 1.0 m from the floor to a shelf.  The worker then slides the crate 3.0 m horizontally along the shelf.  Determine the total amount of work exerted on the crate.

Answer 1

Solution.

$P=100N;$

$h=1.0m;$

$l=3.0m;$

$A= F\sdot s;$

$A =Ph;$

$A=100N\sdot1.0m=100J;$

Answer: $A=100J.$