1. A human tissue cell has a diameter of the order 1.0µm. Assuming each cell occupies a cube of 1.0 µm on one side, estimate the number of cells in 1.0cm3 of tissue.
Solution.
d=1.0μm=10−6m;d=1.0\mu m=10^{-6}m;d=1.0μm=10−6m;
V=1.0cm3=10−6m3;V=1.0cm^3=10^{-6}m^3;V=1.0cm3=10−6m3;
V1=d3;V_1=d^3;V1=d3;
V1=(10−6)3=10−18m3;V_1=(10^{-6})^3=10^{-18}m^3;V1=(10−6)3=10−18m3;
N=VV1;N=\dfrac{V}{V_1};N=V1V;
N=10−610−18=1012;N=\dfrac{10^{-6}}{10^{-18}}=10^{12};N=10−1810−6=1012;
Answer:N=1012.N=10^{12}.N=1012.
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