Question

A tank used for filling helium balloons has a volume of 0.600 m³ and contains 3.00 mol of helium gas at 30.0ºC. Assume the helium behaves like an ideal gas

Answer 1

Solution.

$V=0.600m^3;$

$\nu=3.00mol;$

$T=303K;$

$pV=\nu RT\implies p=\dfrac{\nu RT}{V};$

$p=\dfrac{3.00mol\sdot8.31J/(molK)\sdot303K}{0.600m^3}=12589.65Pa;$

Answer:$p=12589.65Pa.$