Question

What is the total thermal energy of 1 mol of an ideal monatomic gas at a temperature of 0°C? (to 2 s.f and in J)

Answer 1

Solution.

$\nu=1 mol;$

$T=273K;$

$U=\dfrac{3}2\nu RT$ ;

$U=\dfrac{3}{2}\sdot1mol\sdot8,31J/(molK)\sdot273K=3402.95J;$

Answer: $U=3402.95J.$