Answer to Question #190489 in Molecular Physics | Thermodynamics for NoName

Question

Up to how many degrees we can heat 5litres of water, the temperature of which is + 20C, using 21 g of pretrol? Answer 44C.how? Q=46 000 000 J/kg c=4200J/kg water. m= 0,021kg petrol m=5kg water. T2=? T1= +20C. Q= q*m= 46 000 000 * 0,021= 966 000 J/kg?

Answer 1

Q= q$\times$m= 46 000 000$\times$0,021= 9660000 (J)

T₂ = T₁ + Q / (m$\times$c) = 20 + 966000 / (5$\times$4200) = 20 + 46 = 66 ^oC.

Answer: T₂ = 66 ^oC.