How much energy is lost by 20 kg copper if it is cooled from 50°C to 30°C?
The specific heat capacity of copper is 0.385 J/goC, which equals 385 J/kgoC
Q=cmΔT=385Jkg⋅°C×20kg×(50°C−30°C)=154000J=154kJQ=cm\Delta{T}=385\frac{J}{kg\cdot{\degree{C}}}\times20kg\times(50\degree{C}-30\degree{C})=154000J=154kJQ=cmΔT=385kg⋅°CJ×20kg×(50°C−30°C)=154000J=154kJ
Answer: 154 kJ
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