Question #186549

Determine the specific enthalpy of wet steam at a pressure of 70 kN m-2 and having a dryness fraction of 0.85.

1
Expert's answer
2021-04-30T11:22:51-0400

H=Cp+pmrT,H=C_p+\frac{pmr}{T}, cp=Cpm,c_p=\frac{C_p}{m},

h=Hm=cp+prT,h=\frac Hm=c_p+\frac{pr}{T},

h=1007+700000.85393=1158 Jkg.h=1007+\frac{70000\cdot 0.85}{393}=1158~\frac{J}{kg}.


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