In a pipe that has a cross-sectional area of 0.5 m^2 and a flow rate of 1.5 m^3/s, what is the average speed of the fluid carried by the pipe? *
Solution:-
So Q = A"\\overline v"
Flow rate is the volume of fluid per unit time flowing past a point through the area A. Here the shaded cylinder of fluid flows past point P in a uniform pipe in time t. The volume of the cylinder is Ad and the average velocity is "\\bar v = \\frac{d}{t}"
So that the flow rate is
"\\boxed{Q={Ad\\over t }=A\\bar v}"
Q(flow rate)= "1.5m^3\/s"
A(cross-sectional area) = 0.5 m2
average speed=
"\\boxed{\\bar v= \\frac{Q}{A}}"
"\\boxed{\\bar v= \\frac{1.5}{0.5}m\/s}"
Answer:-
"\\boxed{\\bar v = 3 m\/s}"
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