How much heat is required to change 200ml of ice at - 22°C into steam 100 °C
λ=3.4⋅105 Jkg,ci=2.1⋅103 Jkg⋅°C,cw=4.2⋅103 Jkg⋅°C,L=2.26⋅106 Jkg,\lambda=3.4\cdot 10^5~\frac{J}{kg},\\ c_i=2.1\cdot 10^3~\frac{J}{kg\cdot °C},\\ c_w=4.2\cdot 10^3~\frac{J}{kg\cdot °C},\\ L=2.26\cdot 10^6~\frac{J}{kg},λ=3.4⋅105 kgJ,ci=2.1⋅103 kg⋅°CJ,cw=4.2⋅103 kg⋅°CJ,L=2.26⋅106 kgJ,
Δt1=0−(−22)=22°C,Δt2=100−0=100°C,\Delta t_1=0-(-22)=22°C,\\ \Delta t_2=100-0=100°C,Δt1=0−(−22)=22°C,Δt2=100−0=100°C,
m=ρV.m=\rho V.m=ρV.
Q=Q1+Q2+Q3+Q4=ρV(λ+ciΔt1+cwΔt2+L),Q=Q_1+Q_2+Q_3+Q_4=\rho V(\lambda+c_i \Delta t_1+c_w \Delta t_2+L),Q=Q1+Q2+Q3+Q4=ρV(λ+ciΔt1+cwΔt2+L),
Q=613 kJ.Q=613~kJ.Q=613 kJ.
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